Binary Tree

1.Binary Tree Preoder, Inorder, Postorder traversal

1

一套模版走天下

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class Solution {
根左右
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> res = new LinkedList<>();
Stack<TreeNode> stack = new Stack<>();
TreeNode cur = root;

while(cur != null || !stack.isEmpty()) {
while (cur != null) {
stack.push(cur);
res.add(cur.val);
cur = cur.left;
}
TreeNode temp = stack.pop();
cur = temp.right;
}
return res;
}
------------------------------------------------------------
左根右
public List<Integer> inorderTraversal(TreeNode root) {
List<Integer> res = new LinkedList<>();
Stack<TreeNode> stack = new Stack<>();
TreeNode cur = root;

while(cur != null || !stack.isEmpty()) {
while (cur != null) {
stack.push(cur);
cur = cur.left;
}
TreeNode temp = stack.pop();
res.add(temp.val);
cur = temp.right;
}
return res;
}
-------------------------------------------------------------
左右根 = 根右左 + 反过来存res
public List<Integer> postorderTraversal(TreeNode root) {
List<Integer> res = new LinkedList<>();
Stack<TreeNode> stack = new Stack<>();
TreeNode cur = root;

while(cur != null || !stack.isEmpty()) {
while (cur != null) {
res.addFirst(cur.val);
stack.push(cur);
cur = cur.right;
}
TreeNode temp = stack.pop();
cur = temp.left;
}
return res;
}
}